Lowest Bit
Time Limit: 1000MS Memory limit: 65536K
题目描述
Given an positive integer A (1 <= A <= 100), output the lowest bit of A. For example, given A = 26, we can write A in binary form as 11010, so the lowest bit of A is 10, so the output should be 2. Another example goes like this: given A = 88, we can write A in binary form as 1011000, so the lowest bit of A is 1000, so the output should be 8.
输入
Each line of input contains only an integer A (1 <= A <= 100). A line containing "0" indicates the end of input, and this line is not a part of the input data.
输出
For each A in the input, output a line containing only its lowest bit.
示例输入
26880
示例输出
28
#includeint main(){ int n; int sum; while(scanf("%d",&n), n != 0) { sum = 1; while( (n & 1) == 0)//这里(n&1)一定要括起来。。&优先级不够高啊。。费了很大劲才知道的。。好吧。我承认我很低级。。 { n /= 2; sum *= 2; } printf("%d\n",sum); } return 0;}